PVC curtains - help with form type 2
As an example the first 30 widths where the strips are hung symmetrically are collected in the next table.
300mm wide strips with one hook (5cm) overlapping - table
Number of strips | Width in mm | Number of strips | Width in mm | Number of strips | Width in mm |
1 | 300 | 11 | 2760 | 21 | 5220 |
2 | 546 | 12 | 3006 | 22 | 5466 |
3 | 792 | 13 | 3252 | 23 | 5712 |
4 | 1038 | 14 | 3498 | 24 | 5958 |
5 | 1284 | 15 | 3744 | 25 | 6204 |
6 | 1530 | 16 | 3990 | 26 | 6450 |
7 | 1776 | 17 | 4236 | 27 | 6696 |
8 | 2022 | 18 | 4482 | 28 | 6942 |
9 | 2268 | 19 | 4728 | 29 | 7188 |
10 | 2514 | 20 | 4974 | 30 | 7434 |
Real width - can be different from the width you entered +-2cm. It is caused by the geometric allocation of hooks on hook-on-track system.
If you want to calculate the real width by yourself keep in mind that one hook is 25mm wide and the gaps between the hooks are 16mm wide together so the width of the curtain can be increased always by 41mm.
To determine the possible widths, we need to determine the coefficient N.
N = (curtain or opening width you set - strip width) / 41mm
E.g. if you want to create about 2m wide curtain with 300mm wide strips, the coefficient N is as follows:
N = (2000mm - 300mm) / 41mm = 1700mm / 41mm = 41.46
In this case, the closest possible widths can be determined by rounding the N coefficient up and down.
Possible curtain width 1 = 300mm + 41 * 41mm = 1981mm
Possible curtain width 2 = 300mm + 42 * 41mm = 2022mm
F.e. if the N coefficient is dividible by six, the 300mm wide strips will hang symmetrically, everywhere with a basic overlap on one hook, ie 54mm.
In other cases, the last PVC strip must be hung with a larger overlap (2 to 6 hook overlap, 95mm to 259mm).